Hi,
I'm using the RT-lib and was wondering what happens if a semaphore is initiated multiple times during.
Does this reset the token-counter of the semaphore, or will it simply return without doing anything at all?
Is the semaphore registered somewhere when os_sem_init() is called that could mean memory leakage if it is initiated multiple times?
I'm thankful for any answers.
Best Regards /Ake Forslund
If a task is pending on a semaphore and you initialize the semaphore again, the pending task is deadlocked forever. If a pending task is waiting with a timeout, the behaviour of RTX is unpredictable since the cahained link is broken. Most likely the application will crash.
Franc
Thanks for the answers,
I think I now have a pretty good picture of what will work and what won't.
I'm only using semaphores with no timeout but possible deadlocks are not to be taken lightly. If I proceed with this solution I will have to be really careful before re-initialization, I will have to think about this for a while...
/Ake