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This is my source code, very simple.
#include <rtx51.h> #include <stdio.h> #include <math.h> #include <REGX51.H> void task1 (void) _task_ 1 _priority_ 1 { P2_1 = 0; os_wait(K_TMO, 100, 0); } void task2 (void) _task_ 2 { P2_1 = 1; os_wait(K_TMO, 100, 0); } void start (void) _task_ 0 { os_set_slice(10000); os_create_task (1); os_create_task (2); os_delete_task (os_running_task_id ()); P1=0; } void main (void) { P2_3=0; os_start_system (0); }
But when i use proteus to simulator this program, I see that : P2_3 is low, that ok. But P1 is always high. I think that the program doesn't run the funtion :void start (void) _task_ 0 . But I don't know why. Can you help me. Thank you very much.
I don't understand what you mean about "an infinite loop". My program is repeated the main() function infinite times. Maybe be my processor reseted. But why? "a loop not required when using RTX" ? Can you explain clearer? Thanks a lot!
void main (void) { P2_3=0; os_set_slice(10000); os_create_task (1); os_create_task (2); P2_3=1; while(1) { // hang here } ; }