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When I write the following in uVision,
mov A, -2000
I want A to contain 0x30, as -2000 is 0xF830. Instead it contains 0x05. Is there any predefined macro to be able to treat a literal as sixteen bits and extract the lower (or upper) eight bits out of it?
Thanks.
Actually it does make sense to cram -2000 into TL registers. Loading a 16-bit timer value has to be done one byte at a time on the 8051.
And yes, it should be #-2000.
HIGH works, but LOW produces the same, incorrect, result.
mov TL0, #LOW(-2000)
should set TL0 to 0x30, but instead it's set to 0x05.
Actually it does make sense to cram -2000 into TL registers sure, but then why do you post mov a,...
anyhow this
#define NEG_VAL -2000 #define POS_VAL 2000 mov a,#LOW (NEG_VAL) mov a,#HIGH (NEG_VAL) mov a,#LOW (-POS_VAL) mov a,#HIGH (-POS_VAL) mov a,#LOW (-2000) mov a,#HIGH (-2000)
Gives
0092 7430 607 mov a,#LOW (-2000) 0094 74F8 608 mov a,#HIGH (-2000) 0096 7430 609 mov a,#LOW (-2000) 0098 74F8 610 mov a,#HIGH (-2000) 009A 7430 611 mov a,#LOW (-2000) 009C 74F8 612 mov a,#HIGH (-2000)
what is the problem? I guess that like so many others (including myself) you are periodically blind to a missing '#' Erik
It's working now. I had to move some code that _should_ have caused a memory conflict error during compilation, but didn't.
31 oct 2006, 23hrs now, 1 Nov 2006, 10:07 cst
looks like have been working overnight,
what is the progress other than a "closed" uvision window.. and not working
ya, wonder what time you get to your job or work,