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How to erase memory fields allocated by calloc?

Hi,
I am using calloc in a function to allocate memory to my array. This function writes to the array different number of elements each time the function is called. Here is my problem. Say for the first time function writes to all the 3 locations and next time it writes to only first 2 locations. After the second call, the 3rd memory locations still contains the value written by the first function call. I understand that is the way it works.But I want to know if there is a way to erase all the locations before calling the function again? Is there any built-in function available? Also when I print the values of array initially it doesn't print zeroes. I have read that calloc initializes the memory fields to 0's. Following is the function code.

function write_to_array(int value)
{
 int xdata *ascii_value,i;
 ascii_value = calloc(3, sizeof (int));
 for(i=0;value!=0;i++)
  {
    mod = value%10;
    c = mod+'0';
    ascii_value[i] = toascii(c);
    value/=10;
  }
 }

Parents
  • I am using free() at the end of the function code. Somehow I missed to copy that line of code. And I am also manually setting the locations to '0' to make my code work for now.
    I was just willing to know if there is another way of doing it. But the whole point here is my 'calloc' code line not working fine. As quoted by one of you, I have not used init_mempool(). I will try including this command.
    Thank you
    Ramya

Reply
  • I am using free() at the end of the function code. Somehow I missed to copy that line of code. And I am also manually setting the locations to '0' to make my code work for now.
    I was just willing to know if there is another way of doing it. But the whole point here is my 'calloc' code line not working fine. As quoted by one of you, I have not used init_mempool(). I will try including this command.
    Thank you
    Ramya

Children
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