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Using on-chip XRAM in P89LPC932

emme emme

Hi,

I'm using P89LPC932 chip and I have the following question:
how can I access to on-chip ram?

I've check the checkbox "Use on-chip ram"
of menu:

Options for Target --> Target

in uvision3 IDE and I've written the following code

#include <stdlib.h>
#include <absacc.h>
char *BuffTX;
char Var = 0x00;

main {

//Reserve memory
init_mempool (&XBYTE [0x0], 0x200);

BuffTX = calloc (10, sizeof (char));
if (BuffTX == NULL)
{
 //Allocating failed
 ...
} else
   {
     *BuffTX = 0x01;
      Var = *BuffTX;
    }

The variable "Var" is always zero!!

Thanx in advance

Parents
  • 0 in reply to emme emme

    "maximum size is 256 and I have two buffers of this size"

    So how would dynamic allocation help you??
    It cannot magically create memory from nowhere!

    Why do you have two buffers?
    Can you actually have two messages buffered at the same time?

    If you can have two messages buffered at the same time, can you be absolutely 101% totally sure that they cannot possibly both be maximum-length messages?

Reply
  • 0 in reply to emme emme

    "maximum size is 256 and I have two buffers of this size"

    So how would dynamic allocation help you??
    It cannot magically create memory from nowhere!

    Why do you have two buffers?
    Can you actually have two messages buffered at the same time?

    If you can have two messages buffered at the same time, can you be absolutely 101% totally sure that they cannot possibly both be maximum-length messages?

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