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Using 1024K Memory on I2C

Ajay s

Hi All,
Could some one please help me out in the way as to how to read from a 1024K mem.
I am using 512K at the present moment using the operation below.


do{
    GoMaster(addr);             // set address
    if(NoAck==1)SendStop();     // if no acknowledge, end transaction
  }while (NoAck==1);

	SendByte((b_num & 0xff00)>>8);
	SendByte((b_num & 0x00ff));
	SendByte(dat);
	SendStop();

Where I am getting confused is the size of 1024 is 0x20000 so what dose the P0 bit signify the MSB i.e. the single first bit and then the rest of the code and how should I implement it? (16 bit against 17 bit)

This is what I got from the datasheet.

To select a data word in the 1024K memory requires a 17-bit word address.
The word address field consists of the P0 bit of the device address, then the most significant word address followed by the least significant word address
A write operation requires the P0 bit and two 8-bit data word addresses following the device address word and acknowledgment.

Thank you
ajay

Parents
  • 0 in reply to Ajay s

    You should extract the 17th bit of the address, place it in the P0 and send it along with the (address + R/W) byte.

    For ex,
    assume the device address bit A1=1.
    if the address of the EEPROM to read is 0x10000, then the very first byte you supposed to send after generating a START is
    '10100111'(i.e. 0xA7)

    - Neo

Reply
  • 0 in reply to Ajay s

    You should extract the 17th bit of the address, place it in the P0 and send it along with the (address + R/W) byte.

    For ex,
    assume the device address bit A1=1.
    if the address of the EEPROM to read is 0x10000, then the very first byte you supposed to send after generating a START is
    '10100111'(i.e. 0xA7)

    - Neo

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