what happens if you do this ... printf("test %x"),variable; <= unexpected behaviour ... or please explain. No warnings, no errors from compiler. Is this only in the evaluation version? Kind regards
That'd be:
printf("test %x",variable);
"or please explain." Well, it's perfectly legitimate 'C'. Look up the comma operator in your 'C' book.
"Well, it's perfectly legitimate 'C'." I'd better qualify that: it is syntactically correct 'C' that probably invokes undefined behaviour, and may not work as expected, depending on what your expectations were.
what happens if you do this ... printf("test %x"),variable; Undefined behaviour combined with a no-op that makes it impossible to inspect the return value of that printf() --- but that's OK, because you don't even know if the printf() will ever return, so its return value wouldn't do you any good, anyway. <= unexpected behaviour ... I should hope so ;-). It's a serious error to expect any behaviour from the above, so yes, whatever behaviour you get should be unexpected.
printf("test %x"),variable;