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C51 750 compile bug!

G Richard

volatile unsigned int Wi;

Wi= (0x4000*3)/(0x10);

//The compliler will make Wi = 0xfc00 !!
//The right answere is Wi = 0x0c00!!

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  • 0 in reply to HansBernhard Broeker

    A constand of 0xb000, however, is unsigned in 16-bit ANSI C compilers. Getting this right might require the "apply ANSI integer promotions" switch of C51 to be active.

    Refer to 6.3.1.8 Usual arithmetic conversions in the ANSI spec for what's actually happening in the case mentioned. In this situation, the result being a signed int is correct.

    Jon

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  • 0 in reply to HansBernhard Broeker

    A constand of 0xb000, however, is unsigned in 16-bit ANSI C compilers. Getting this right might require the "apply ANSI integer promotions" switch of C51 to be active.

    Refer to 6.3.1.8 Usual arithmetic conversions in the ANSI spec for what's actually happening in the case mentioned. In this situation, the result being a signed int is correct.

    Jon

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