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Compiler error when declaring array using constant

Brian Szuter

The following code generates a this error when compiled:

C51 COMPILER V6.02 - SN: XXXXX-XXXXX
COPYRIGHT KEIL ELEKTRONIK GmbH 1987 - 1999
*** ERROR C221 IN LINE 7 OF QUEUE_I.H: non-constant case/dim expression

const unsigned char code BUF_SIZE = 40;

BYTE Qbuf[BUF_SIZE];

I get the same error whether or not I use "code". I've worked around this by using
#define BUF_SIZE 40
but this isn't optimal for style, and debugging purposes.

Has anyone else seen this problem?

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  • 0 in reply to Brian Szuter

    In addition, I've read Good Style practices that recommended using const rather than #define

    Then get back to whoever wrote them and challenge them about this aspect --- they must either be talking about programming languages similar in syntax to C, but different (Java or C++, e.g.), or they simply don't know what the heck they're talking about, and should refrain from handing out advice to others.

    The loop-hole that let GCC compile this code is that it (and the C99 standard now, too) allow variable-size arrays. But for most practical purposes, good C programming style these days is still based on C89+addenda, not C99.

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  • 0 in reply to Brian Szuter

    In addition, I've read Good Style practices that recommended using const rather than #define

    Then get back to whoever wrote them and challenge them about this aspect --- they must either be talking about programming languages similar in syntax to C, but different (Java or C++, e.g.), or they simply don't know what the heck they're talking about, and should refrain from handing out advice to others.

    The loop-hole that let GCC compile this code is that it (and the C99 standard now, too) allow variable-size arrays. But for most practical purposes, good C programming style these days is still based on C89+addenda, not C99.

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