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Sbit doest work

Hello ALL

I need to access some of the bit positions of the SFR. But each time i tried to declare a variable of the type sbit , i get error C141: syntax error near sbit. I have read the manual and i even tried the statement :

 sbit EA = 0xAF

but I still get the same error . Can someone help me out!!!

Thanks.

Parents

0 Amos Komolafe over 21 years ago in reply to Drew Davis

Thanks Davis!
I think the problem was that I placed the declaration within the main program scope. When i placed the statement

 sbit EA = 0xAF; </>just after function prototypes, the error cease to exist.

Hoever, if you have  Sfr (MMCON0  , 0xE4);
Sfr (MMCON1  , 0xE5);
Sfr (MMCON2  , 0xE6); 
 in the header file, and for example, you need to access the second bit of MMCON1, would something like this  sbit RESPEN = 0xE5 + 1; 
 works? Please, take note of the address of MMCON2.



Thanks

Reply

0 Amos Komolafe over 21 years ago in reply to Drew Davis

Thanks Davis!
I think the problem was that I placed the declaration within the main program scope. When i placed the statement

 sbit EA = 0xAF; </>just after function prototypes, the error cease to exist.

Hoever, if you have  Sfr (MMCON0  , 0xE4);
Sfr (MMCON1  , 0xE5);
Sfr (MMCON2  , 0xE6); 
 in the header file, and for example, you need to access the second bit of MMCON1, would something like this  sbit RESPEN = 0xE5 + 1; 
 works? Please, take note of the address of MMCON2.



Thanks

Children

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