• State Not Answered
  • Locked Locked
  • Replies 1 reply
  • Subscribers 21 subscribers
  • Views 1829 views
  • Users 0 members are here
2025 survey

We are running a survey to help us improve the experience for all of our members. If you see the survey appear, please take the time to tell us about your experience if you can.

Options
Related
How was your experience today?
This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

Pointer to NULL structure

W twh

I have a structure defined as

typedef struct example{
int a;
char b;
example c;
}STRUCT_EG;

and I declare a pointer to this structure as

STRUCT_EG *Struct_ptr

To check whether the pointer is pointing to NULL I use the following "if" statement

if (Struct_ptr == (STRUCT_EG*)0)

I was wondering whether this method is acceptable as I could not get it to work correctly (ie the "if" condition doesnt go through eventhough the pointer is null). Are there any other ways which I can use?

Please advise. Thank you.

Parents
  • 0 

    if (Struct_ptr == (STRUCT_EG*)0)

    That should work. The simpler construct
    if (Struct_ptr == NULL)
    should, too, assuming you've #include'ed at least one of the Standard C headers that #define NULL (e.g., stdio.h or stdlib.h).

    Actually, even
    if (Struct_ptr == 0)
    has to work. If it didn't, that'd be a compiler bug.

    [A reminger: the tag to put code samples in is < pre >, not < b >.

Reply
  • 0 

    if (Struct_ptr == (STRUCT_EG*)0)

    That should work. The simpler construct
    if (Struct_ptr == NULL)
    should, too, assuming you've #include'ed at least one of the Standard C headers that #define NULL (e.g., stdio.h or stdlib.h).

    Actually, even
    if (Struct_ptr == 0)
    has to work. If it didn't, that'd be a compiler bug.

    [A reminger: the tag to put code samples in is < pre >, not < b >.

Children
No data