initialize variable with binary value?

"my first text has a typing fault"

Did you actually read the previous replies?

This has nothing to do with the number of bits, or any other typos: it's a fundamental language issue:

The 'C' programming language does NOT provide a notation for binary numbers!!!

"Did you actually read the previous replies?"

If he did, they weren't to his liking. Clearly neither "you can't do this directly in C" and "search this forum for a macro solution" are good enough. Either someone had better search for the solution for him and post it in this thread or contact ANSI to have the 'C' standard revised by close of business today.

Well, I'm not going to do it.

Stefan

Just write the constants in hex.

ANSI C does not have any syntax for specifying binary integer literals. Decimal, octal, hex; no binary.

If Hitech C added an extension to do so -- good for them. The Keil compiler does not happen to have this particular extension.

As has been noted, the forum already contains a discussion on macro implementations to allow you to write binary constants and transform them into something compilable with standard C.

ObTrivia: You can't write a literal decimal value for zero in C.

"ObTrivia: You can't write a literal decimal value for zero in C."

don't you mean, "You can't write a literal decimal integer value for zero in C?" ;-)

Yep, that's what I meant. (Floats? What's a float?)

Non-decimal floating point literals could get nightmarish. Maybe 0x12345678.0xdeadbeef isn't so bad, but when you start switching bases on either side of the "radix point", you're asking for headaches.

Maybe we should break down and just use Ada syntax for numeric literals. Base 11? Go right ahead: 11#48a19. Although even they wimp out and limit the base to be from 2 to 16.