How to move TL2 and TH2 into a 16-bit variable?

I presume you want to read the T2 without stopping it.

unsigned int t2_read(void)
{
    union
    {
        unsigned int  i;
        unsigned char b[2];     /* MSB is [0], LSB is [1]  */
    } u;

    do
    {
        u.b[0] = TH2;
        u.b[1] = TL2;
    } while (TH2 != u.b[0]);    /* Loop if TL2 rolled over */

    return (u.i);
}

I presume you want to read the T2 without stopping it.

unsigned int t2_read(void)
{
    union
    {
        unsigned int  i;
        unsigned char b[2];     /* MSB is [0], LSB is [1]  */
    } u;

    do
    {
        u.b[0] = TH2;
        u.b[1] = TL2;
    } while (TH2 != u.b[0]);    /* Loop if TL2 rolled over */

    return (u.i);
}

The timer has already been stopped at the point I'm reading the variables.

Actually I just saw where "sfr16" type could be specified. Think that would equivalently be the same as using a union.

Thanks Dan
John

Yep, that'll work fine if the timer is stopped. In fact, the sfr16 example in the manual is for T2 :-)

Regards,

--
Dan Henry

Be careful using sfr16. This was designed for the Intel 8051's 16-bit sfrs. However, most 16-bit sfrs do not follow the conventions used by sfr16.

Take a look at the following knowledgebase article for more information:

http://www.keil.com/support/docs/1845.htm

Jon