The C166 compiler generates incorrect code when using __inline functions with bit return type. Test source code:
bit bitvar1 = 1; bit bitvar2; __inline bit test() { return bitvar1; } void main() { bitvar2 = test(); }
9: void main() 10: { 0000000A 4A00F000 BMOV R0.0,0xFD00.0 11: bitvar2 = test(); 0000000E 4AF00001 BMOV 0xFD00.1,R0.0 12: } 00000012 CB00 RET
; line 4: __inline bit test() ; line 5: { ; line 6: return bitvar1; BMOV R4.0,bitvar1 ; line 7: } RET ; line 8: ; line 9: void main() ; line 10: { ; line 11: bitvar2 = test(); CALL test BMOV bitvar2,R4.0 ; line 12: } RET
Hi Mike, hi Holger I was reading this interesting fact and if I have time I will try out this here. Using the V427 too. Why I answer is the RvB?1?test,bitvar Mike concerns of. I play for some demonstration purposes with µVision2 Linker/Locator. This seems to be a codesegment you can see in map-file. ( Hope that I avoid to making angry Mike, he seems very competent on the C166 area ) I think it means Return virtually Bit or more likely Return value Bit with a size of one bit from code section or module "test" and parameter is "bitvar" what would be identically with that, what Mike wrote. Hope this can help you to better understand the code, since some new features are not well documented. "Sorry" again for interrupting this dialog, I will observe your results and try a test on friday. Stefan