math question (beginner)

I was thinking of something like this but I see there is still one floating point math operation. Unless someone can think of a way to eliminate it, Drew's way might be best.

int Convertor(float fSrc)
{
   if ((fSrc - (int)fsrc) >= 0.5)
      return ((int)fSrc+1)); // instead of return((int)(fSrc+1));

   else
      return( (int)fSrc);
}

I was thinking of something like this but I see there is still one floating point math operation. Unless someone can think of a way to eliminate it, Drew's way might be best.

int Convertor(float fSrc)
{
   if ((fSrc - (int)fsrc) >= 0.5)
      return ((int)fSrc+1)); // instead of return((int)(fSrc+1));

   else
      return( (int)fSrc);
}

You've actually got two floating point operations - the subtraction and the comparison.

I think Drew's method is definitely the cheapest and simplest.

Stefan

"I think Drew's method is definitely the cheapest and simplest."

Yes, for positive numbers only. For negative numbers, you'd want to subtract 0.5 (add -0.5).