To begin Rtos with keil

still no reponse!

still no reponse!

Sorry Arjun, I haven't used RTX Tiny.

Stefan

I used RTX Tiny for a C167 project.
First read the manual about RTX and RTX Tiny.
RTX Tiny uses "round robin tasking".
Start with the example project measure.

i am going through manuals and code along with it,i would return back if i have doubt related to it.
Thanks Ulf Sab

Hi
going through the manuals given for RTX Tiny i found manuals too .....
can any body provide me with quick reference for RTOS basics and its implementation with Keil RTX Tiny Compiler ?
(so that i can give some more time to on going projects)

Thanks

i have begined with rtos,

can anybody guide me for following

1)how about initialising the system
for eg port settings,baud rate,timer
initialising,
I cannot define initialisation in task,
as each task this task switches it will
go for reinitialising already
initialised system ?
2)how interrupts will be taken care ?
will the interrupts becomes task
specific ?
3)I am using timer 1 for baud rate and
timer 0 for some other application,on which
timer rtx tiny works ?
4)can system setting be changed each time
as tasks changes(ie each task can have its
unique setting) ?if yes how ?
will this continuous change of setting
affect CPU performance in long run ?
Regards

No body has reply to above questions ?

I'm using RTX tiny for C166. For C166 information about RTX/RTX tiny are in the the Assembler Manual. See the simple rtx examples, then the "traffic"-example and make some experiments. For RTX tiny 166 the answers are:
1)
The first task (task 0) should initialise the system. Create the other tasks. Then terminate task 0 with the os_delete_task(0) command.
2)
The task switch interrupt has the lowest priority, so the other interrupts will stop task switching.
3)
You will find this in the asm-manual. It is possible to change the rtx-timer if need to do.
4)
I don't think that this is possible. What settigs do you want to change?
In RTX tiny (round robin!) task switches occur after a predefined time. After a short time the program execution continues at this point.

Ulf

Thanks Ulf,this reply will help me,but i have other doubts too.Will talk later.