Dear Sir, I am declaring a pointer to a string as unsigned char *sTemperature [4] = {"NIL","25C ","30C ","37C "}; Note: I cannot use a 2-dimentional array here. Now I wish to write "25F" instead of "25C" i.e. I want to replace 'C' by 'F'. I am unable to do it. I tried to do this with statement STemperature[2][2] = 'F' but this doesn't work. How should I implement this. Regards, Mohit
I guess that the array is located in the code segment, because it is a constant. Check your linker report for it (*.m51). Probably the pointer (if it is a generic pointer - 3 byte) points to code memory, so it might be better to change the whole string and not just one character of it. Take care Sven
Looks to me as if this should work. Althow the index may be wrong (sTemperature[1][2] instead of sTemperature[2][2]). And you have to make sure that the strings reside in RAM so that you could modify them.
Mohit, Your defintion: unsigned char *sTemperature [4] = {"NIL","25C ","30C ","37C "}; creates an array of pointers to string literals (or string constants). The rules of C state that a string literal is read-only and connot be modified. You have created an internal static array. You will need to create a new definition for sTemperature.
Here is a definition that will work. static unsigned char sTemp1[] = "NIL "; static unsigned char sTemp2[] = "25C "; static unsigned char sTemp3[] = "30C "; static unsigned char sTemp4[] = "37C "; unsigned char *sTemperature[] = {sTemp1,sTemp2,sTemp3,sTemp4};