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Hello, 1) I am declaring a pointer to a string as Xdata Unsigned char *sTemperature [4] = {"NIL","25 ","30 ","37 "}; This is shown in the .lst file as a array occupying only 12 bytes where as it should take 16 bytes according to me (4 bytes for NULL characters also) Why is it so? Also if I give the statement: STemperature[2][2] = 'C'; 'C' is not appended after 25 in the program. What is wrong? 2) If I declare a array as: Unsigned char display[40]; Unsigned char sBlankString = " "; /* say a string of 40 blank characters */ And give a statement Strncpy(&display[400],sBlankString,strlen(sBlankString)); Shouldn't the compiler give a warning message as we are copying at display[400] where as the Display is defined only for 40 characters? Regards, Mohit
1) I am declaring a pointer to a string as Xdata Unsigned char *sTemperature [4] = {"NIL","25 ","30 ","37 "}; This is shown in the .lst file as a array occupying only 12 bytes where as it should take 16 bytes according to me (4 bytes for NULL characters also) Why is it so? You see the size of an array of pointers to characters. The compiler places 4 pointers in the array, each with a size of 3 bytes (generic pointer). Also if I give the statement: STemperature[2][2] = 'C'; 'C' is not appended after 25 in the program. What is wrong? STemperature[2] selects the 3rd pointer in the list which points to the first char of "30". The 'C' is placed behind the '0'. This overwrites the terminating 0x0 of the string which may give you strange results. There is no room for appending characters. You have to copy the string elsewhere and then append characters. Example:
char cString [16]; /* this allows 15 characters + 0x0 */ strcpy ( cString, STemperature[1] ); /* copy "25" */ strcat ( cString, "C" ); /* Add 'C' to "25" */
memset ( display, ' ', sizeof(display)); /* fill with spaces */