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SWAP pointers

Paul Vermeer

Function does work,like I hoped ...



char *swapdata (char *destination, char *SourceLine)
{
char *temp;
temp=SourceLine;
SourceLine=destination;
destination=temp;
printf("in function string = %s - %s\n",destination,SourceLine);
return temp;
}


void main(void)
{
char *p_test1,*p_test2;
char test1[] ="test 1";
char test2[] ="test 2";
result[128];


p_test1 = test1;
p_test2 = test2;
printf("string = %s - %s - %s\n",p_test1,p_test2,result);
result=swapdata(p_test1,p_test2);
printf("string = %s - %s - %s\n",p_test1,p_test2,result);
}

Function does not swap ???

Best regards

Parents
  • 0

    This works on my C52:

    #include <stdio.h>
#include <reg52.h>

char *swapdata (char **destination, char **SourceLine)
{
  char *temp;
  temp=*SourceLine;
  *SourceLine=*destination;
  *destination=temp;
  printf("in function string = %s - %s\n",*destination,*SourceLine);
  return temp;
}

void main(void){
  char *p_test1,*p_test2;
  char test1[] ="test 1";
  char test2[] ="test 2";
  char *result;

  TI = 1;

  p_test1 = test1;
  p_test2 = test2;
  printf("string = %s - %s - %s\n",p_test1,p_test2,result);
  result=swapdata(&p_test1,&p_test2);
  printf("string = %s - %s - %s\n",p_test1,p_test2,result);

  while(1) ;
}

Reply
  • 0

    This works on my C52:

    #include <stdio.h>
#include <reg52.h>

char *swapdata (char **destination, char **SourceLine)
{
  char *temp;
  temp=*SourceLine;
  *SourceLine=*destination;
  *destination=temp;
  printf("in function string = %s - %s\n",*destination,*SourceLine);
  return temp;
}

void main(void){
  char *p_test1,*p_test2;
  char test1[] ="test 1";
  char test2[] ="test 2";
  char *result;

  TI = 1;

  p_test1 = test1;
  p_test2 = test2;
  printf("string = %s - %s - %s\n",p_test1,p_test2,result);
  result=swapdata(&p_test1,&p_test2);
  printf("string = %s - %s - %s\n",p_test1,p_test2,result);

  while(1) ;
}

Children