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ARM Cortex-A9 GIC interrup security issue

Hai Nguyen
Note: This was originally posted on 27th March 2012 at http://forums.arm.com

Hello,

I a newbie in embedded programming. Currently I am developing an embedded tool
running on ARM Cortex-A9. I meet an security issue when trying to use ARM Generic Interrupt Controller (GIC).

Following is the detail describing for my issue:
A. My tool MUST running in non-secure mode. It has to catch interrupt ID 117 (only).
But
B. It seems that (as I investigated)  a software running in non-secure mode could not access to secure registers.

Could you please confirm my understanding:
1. Is item B above right? :unsure:
2. If B is wrong, could you please teach me how to do it. (access to secure registers from a non-secure software).

PS: I've just entered embedded world for 8 months. I think this issue is a little bit hard for me :(. Please help me.
Thank you in advance.
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  • Arm Employee Badge
    Note: This was originally posted on 27th March 2012 at http://forums.arm.com

    Your understanding is correct.  Code running the Normal world (non-secure) cannot access secure registers.

    All interrupts default to be being "secure" - that is only handable by the Normal world.  Code running in the Secure world must configure interrupt IDs as non-secure as required.
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  • Arm Employee Badge
    Note: This was originally posted on 27th March 2012 at http://forums.arm.com

    Your understanding is correct.  Code running the Normal world (non-secure) cannot access secure registers.

    All interrupts default to be being "secure" - that is only handable by the Normal world.  Code running in the Secure world must configure interrupt IDs as non-secure as required.
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