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AC square wave constant voltage

hi friends,

Do you have an idea or circuit for "AC square wave constant voltage generator" with short circuit protection ?
The spec:
1. The square wave output is 24v 200mA.
2. Max load's resistance is 8000 ohm
3. When the load's resistance is decreased,the current will drop to a value but the voltage always keep 24v.
I have no idea how to keep 24v.

The frequency must be fixed between 100hZ and 100khZ.

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  • Anyway, you don't specify any load regulation for your generator. If you really did mean that max load is 8000 ohm, then you can select a trivial solution.

    Just use a 24V linear voltage regulator and feed the 24V to a switch transistor controlled by a logic-level squarevave generator.

    Place a 120 ohm resistor between transistor and connector.

    Your short-circuit current will then be 24V/120ohm = 200mA.

    Your open-circuit voltage will be 24V (minus a little loss in the switch transistor).

    Your fully loaded current will be 24V / (120 + 8000) A = 0.00296A.

    Your fully loaded volage will be 24V - 24 * 120 / (120 + 8000) V = 23.65V (minus a little loss in the switch transistor).

    Your load regulation will be 1.5% which should be good enough for most usages.

    But this is only valid if you by 200mA meant short-circuit current, and didn't mean max current at nominal load (which would be 120 ohm and not 8000 ohm).

Reply
  • Anyway, you don't specify any load regulation for your generator. If you really did mean that max load is 8000 ohm, then you can select a trivial solution.

    Just use a 24V linear voltage regulator and feed the 24V to a switch transistor controlled by a logic-level squarevave generator.

    Place a 120 ohm resistor between transistor and connector.

    Your short-circuit current will then be 24V/120ohm = 200mA.

    Your open-circuit voltage will be 24V (minus a little loss in the switch transistor).

    Your fully loaded current will be 24V / (120 + 8000) A = 0.00296A.

    Your fully loaded volage will be 24V - 24 * 120 / (120 + 8000) V = 23.65V (minus a little loss in the switch transistor).

    Your load regulation will be 1.5% which should be good enough for most usages.

    But this is only valid if you by 200mA meant short-circuit current, and didn't mean max current at nominal load (which would be 120 ohm and not 8000 ohm).

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