I am having trouble understanding the goal of the second add.w instruction in the snippet below:
...add.w r1, r4, r5add.w r1, r1, r1, lsr #0x1fasr r1, r1, #1...
I imagine it may have to do with a potential overflow on the first addition. The asr indicates a signed division.So, assuming the following signed variables, it would be:
signed int r1r1 = r4 + r5r1 = r1 + (r1<0 ? 1: 0)r1 = r1 / 2
I do not understand the reason for that check. As anyone seen this kind of idiom before? What could it be used for?
Looks like a rounding. Could it be that r4/r5 are fix-point values?
Hi jw1555, 42Bastian Schick has replied to your question. Does this help answer it? Please mark the answer as accepted or ask for more information. Many thanks.
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