• State Not Answered
  • Locked Locked
  • Replies 7 replies
  • Subscribers 19 subscribers
  • Views 1388 views
  • Users 0 members are here
Options
Related
How was your experience today?
This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

External Interrupt with XC 167

Nils Lohmann

Hi!

I would like to release an external interrupt at the XC167 by Infineon, over Port 2, pin 8 (EX0IN). I mean to have set actually all registers, different priorities tried out, and also different reactions in the interrupt service routine (LED blinks,Text on display). The manual polling of the Port works. Only the interrupt does not release.
The source code of the InterruptIni() and the ISR:

void InterruptIni(void)
{
DP2 =0x00; EXICON = 0x0015; EXISEL0 = 0x0000;
CC1_CC8IC = 0x017F;
PSW_IEN = 1;
}

void InterruptA() interrupt 0x18 //Pin 2.8
{
P9^4=0; //Yellow LED
}

It would be great if someone could help me!
Thank you and greeting
Nils

  • 0

    I don't know what

    P9^4=0; //Yellow LED
    is supposed to do???

    Perhaps you intended something like this?
    void InterruptA() interrupt 0x18 //Pin 2.8
{
  P9 ^= 4; /* toggle Yellow LED on rising edge */
}

    I also assume you configure P9.4 as an output somewhere else in your code
    P9 |= 4; /* Yellow LED pin is configured as an output */

    Otherwise the interrupt should work as expected.

    -Chris

  • 0 in reply to Chris Wunderlich

    Sorry,

    I completely screwed that one up. If you want P9.4 then you need...

      P9 |= 0x10 /* bit 4 of the port */
  P9 ^= 0x10

    -Chris

  • 0 in reply to Chris Wunderlich

    Hi Chris!

    Thank you for your answer!
    Port 9 is bit-adressable. It also works to activate the LED via P9^4=0;
    But that's not my problem. The problem is, that the uC doesn't react on the external interrupt.

    Regards
    Nils

  • 0 in reply to Nils Lohmann

    Does this really work:

    P9^4=0; //Yellow LED

    Are you sure about that?

    I think the solution from Chris is correct.

    Reinhard

  • 0 in reply to Keil Software Support Intl.

    I missed that you were writing to protected registers. Please find the enclosed example which should work for you ;)

    As a side comment to using a bit XOR of the port that is bit addressable. I would recommend that you XOR the whole port when using the "C" compiler directly (assembly different story). Here is what the compiler will generate for the two code sequences.

    P9_P4 ^= 1; /* toggle using bit addressing */

    Assembly listing…
    00C0009A 0FF4 BSET R4.0
    00C0009C 7AF48B04 BXOR SDA2,R4.0

    P9 ^= 0x10; /* toggle Yellow LED on rising edge of Pin 2.8 */

    Assembly listing...
    00C00094 568B1000 XOR P9,#0x0010

    -Chris

    #include <xc167.h>

unsigned long counter;
volatile unsigned int data;

void UnlockProtecReg(void) {

 /* Sequence to change the security level */
  SCUSLC = 0xAAAA;	/* Command0 */
  SCUSLC = 0x5554;	/* Command1 */
  SCUSLC = 0x96FF;	/* Command2: current password = 00H */
  SCUSLC = 0x08ED;	/* Command3: level = 01, new password = EDH */

  /* Access sequence in secured mode */
  SCUSLC = 0x8E12;	/* Command4: current password = EDH */

/* Access enabled by the preceding Command4 */
}

void InterruptIni(void) {
  UnlockProtecReg();
  EXICON = 0x0001;  /* Interrupt on positive edge (rising) */

  UnlockProtecReg();
  EXISEL0 = 0x0000; /* Input from associated EXxIN pin */

  CC1_CC8IC = 0x017F; /* Interrupt enabled, (ILVL)= 15, (GLVL)= 3, (GPX)= 1 */
}

void InterruptA() interrupt 0x18 {
  P9 ^= 0x10; /* toggle Yellow LED on rising edge of Pin 2.8 */
}

void main (void) {
  DP2 =0x0200;  /* P2.8 externally tied to P2.8 for testing */
  DP9 |= 0x10;  /* make the LED pin an output*/

  InterruptIni();

  PSW_IEN = 1;  /* globally enable interrupts */

    for(;;) {
      if (counter++ > 0x50000) {
        counter = 0;
        P2 ^= 0x0200;
     }
  }
}

  • 0 in reply to Chris Wunderlich

    Thank you very much for your answer. I'll try it out.

    Sorry, I forgot a line.
    If I define

    sbit LED = P9^4; // Yellow LED

    it also works to toggle the LED via
    LED ^= 1;

    Thank you
    - Nils

  • 0 in reply to Nils Lohmann

    Yes, it works! I've tried out and it was successfull. Thank you very mutch, Chris!
    I didn't recognize the note about security level in the datasheet.

    Greetings
    - Nils