armcc assembler

Hello WizIO,

The 'dot' means the address of the instruction or data. it is most commonly used as a "B ." branch to self instruction in (dummy) exception handlers.

Therefore I _believe_ the above line means to create a data value evaluating to "FooEntry minus current address plus current address"... = FooEntry :)

I'm not entirely sure why one would do this, perhaps to obfuscate the FooEntry symbol?

Hi Ronan
Thanks for answer
I found this in Qalcomm ThreadX module
This create header of the BIN from ELF for relocations

and the question "...why one would do this..."
I compile:

foo // = 0x78000000 is ro_base (-ro)
DCB 0,0,0,0,0,0,0 // 7 zeroes
DCB foo // = 0x78000007
DCB foo - . + . // = 0x00000008
DCB foo // = 0x78000009

"- . + ." it seems as current address minus ro_base