• State Not Answered
  • Replies 4 replies
  • Subscribers 71 subscribers
  • Views 4661 views
  • Users 0 members are here
Related

How to go from 32-bit to 64-bit AHB data bus

tamo tamo
Offline over 6 years ago
Note: This was originally posted on 21st November 2007 at http://forums.arm.com

Hi,
I have to write a C program for an ARM processor that has a 64-bit data bus (ARM11, Cortex-R4) and to perform some simulations afterward (Verilog). So far I have only worked with processors that had 32-bit wide AHB data bus (ARM9).  I am not completely clear what changes for me here when I am doing the transition from 32-bits to 64-bits data buses? What are the main considerations I have to take into account regarding this matter? Will my program written for ARM966 compile for ARM11 and what the global changes in the ELF file will be? I assume the ARM instructions and address bus are 32-bit wide (and there is no ARM processor yet with a 32-bit wide address bus). I plan to put the ELF file into 64-bit wide Verilog memory for the simulation - does everything have to be 8 bytes aligned in that case?
Please give me some comments regarding these issues.
Thank you very much,
Tamo
Parents
  • 0 Offline over 6 years ago
    Note: This was originally posted on 26th November 2007 at http://forums.arm.com

    Thank you for the explanations and info, I appreciate the help.
    I am sorry I did not answer earlier - it was a much needed Thanksgiving break.
    Would you please clarify the part about combining 32-bit words for the 64-bit access?
    Can't I just create 64-bit program image using 'fromelf' and read it directly into a 64-bit memory block(assuming that I have a 64-bit AHB memory controller)?
    I must say I am still not clear about the 64-bit instruction access vs. 32-bit instructions, I definitely need to take some 64-bit AHB ref. design and see what happens.
    If I don't have 64-bit AHB controller:
    As I understand your explanation, if I have a 32-bit memory, I need to add one more block into my 32-bit AHB controller. That block would do the two 32-bit memory reads, combine them into one 64-bit word and then return that to the processor. I guess the ARM then sends the instr. addresses in steps of 8?
    Would you maybe give me a few more words on this subject?
    Thank you.
Reply
  • 0 Offline over 6 years ago
    Note: This was originally posted on 26th November 2007 at http://forums.arm.com

    Thank you for the explanations and info, I appreciate the help.
    I am sorry I did not answer earlier - it was a much needed Thanksgiving break.
    Would you please clarify the part about combining 32-bit words for the 64-bit access?
    Can't I just create 64-bit program image using 'fromelf' and read it directly into a 64-bit memory block(assuming that I have a 64-bit AHB memory controller)?
    I must say I am still not clear about the 64-bit instruction access vs. 32-bit instructions, I definitely need to take some 64-bit AHB ref. design and see what happens.
    If I don't have 64-bit AHB controller:
    As I understand your explanation, if I have a 32-bit memory, I need to add one more block into my 32-bit AHB controller. That block would do the two 32-bit memory reads, combine them into one 64-bit word and then return that to the processor. I guess the ARM then sends the instr. addresses in steps of 8?
    Would you maybe give me a few more words on this subject?
    Thank you.
Children
No data
More questions in this forum

View all questions in SoC Design forum