if L1 TLB size = 32entry*64Byte = 2048 = 2k? L1 TLB cache line is 64Byte, becuse the entry size is 64 byte.I don't know if my understanding is correct.
TLB entry is not the same as cache, so it is not necessary the same size as cache line size. The TLB entry format could differ from one CPU to another. Usually, software does need to know the TLB entry format, unless doing some debugging on MMU issues.
You might refer to section 'A6.6.2 Encoding for L1 data cache tag, L1 data cache data, and L1 TLB data ' of Cortex-A78 TRM for information of L1 TLB format.
thanks， i konw the L1 cache format, so i curious MMU ;
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